《置换反应》例题讲解

$Zn + H _ {2} SO _ {4} = ZnSO _ {4} + H _ {2} \uparrow$

$Ba ( OH ) _ {2} + H _ {2} SO _ {4} = BaSO _ {4} \downarrow + 2 H _ {2} O$

$4 Fe ( OH ) _ {2} + O _ {2} + 2 H _ {2} O = 4 Fe ( OH ) _ {3}$

$2 Hg O \stackrel {\Delta} {=} 2 Hg + O _ {2} \uparrow$